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9x^2-64x-1088=0
a = 9; b = -64; c = -1088;
Δ = b2-4ac
Δ = -642-4·9·(-1088)
Δ = 43264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{43264}=208$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-208}{2*9}=\frac{-144}{18} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+208}{2*9}=\frac{272}{18} =15+1/9 $
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